Inverse of a Square Matrix
Objective: Use the inverse of a square matrix to solve linear
systems
Reading Assignment: Pages 159 through 169
Class Notes:
Identity Matrix
"1" is the identity for multiplication, when you multiply a
number by 1, the product is the same as the number. Matrix multiplication
also has an identity matrix, I. The identity matrix is a square
matrix (same number of rows and columns) with 1's in the principal diagonal
and
0's everywhere else in the matrix. The 2 x 2 identity matrix is 
Example
1:

Solution:
Using the calculator, 
Inverse of a Square Matrix
is the multiplicative inverse for the number 2 (the product of a number
and its multiplicative inverse equals the multiplicative identity, 1).
Matrix multiplication also has an identity matrix, the product of a
matrix A and it inverse
equals
the identity matrix, I.
Example 2:
Show that
is
the inverse matrix for the square matrix 
Solution:
For square matrices,
.
Using the Calculator to multiply the matrices produces

Finding
the inverse of a square matrix
There is an algorithm using row operations to find the inverse of a square
matrix. This procedure can become very tedious for large matrices.
Luckily, the calculate will find the inverse of a square matrix.
Example
3:
Find the inverse for the matrix
Solution:
 |
Using the TI-83 to Find the Inverse
of a Square Matrix |
1. Enter the matrix into the calculator.
A. Access the Matrix menu by pressing
[2nd] and [ ].
B. Use the right arrow key to highlight
"EDIT" and press [ENTER].
(The matrix will be stored in matrix A.)
C. Enter the dimensions of the
matrix. In this case, type in 3, [ENTER], and 3,
[ENTER].
D. Type in each element of the matrix,
pressing [ENTER] after each value.
E. Exit the Matrix Menu by pressing [2nd]
and [MODE]. |
Matrix Equations
A matrix equation is comprised of a square matrix (n x n) A, a column matrix (n
x 1) X, and a column matrix (n x 1) B. These matrices are combined to form
AX = B. To solve this matrix equation, multiply both sides of the equation
by
. Then X =
(B).
Starting with: AX
= B
(AX) =
(B)
(
A)X =
(B)
Since (
A) = I, the identity matrix
IX =
(B)
Since IX = X
X =
(B)
Example 4:
Use matrix equations and the inverse matrix to solve the linear system:
x + 2y + 3z = 4
y + z = -2
2x + 2y = 3
Solution:
Set up matrixes A, X, B

Use
the calculator to find
.

Store the inverse matrix in matrix
D.
1. Press "STO:"
2. Access the Matrix menu by pressing
[2nd] and [
].
3. Use the down arrow to highlight
"4: [D]" and press [ENTER].
4. Press [ENTER]. (The inverse will be stored in matrix D.)
Use matrix multiplication to solve X =
(B)
. 

x
= 5.75, y = -4.25, and z = 2.25
Testing
the solution: x + 2y + 3z = 5.75 + 2(-4.25) + 3(2.25) =
4.75 - 8.5 + 6.75 = 4
y + z = -4.25 + 2.25 = 2
2x + 2y = 2(5.75) + 2(-4.25) =
11.5 - 8.5 = 3
Example
5:
Use matrix equations and the inverse matrix to solve the linear system:
A corporation has taxable income of $10,000,000. The federal tax rate is
30%, the state tax rate is 8%, and the local tax rate is 4%. The federal
taxes are based on the income after the state and local taxes are
deducted. The state taxes are based on the income after the federal and
local taxes are deducted. The local taxes are based on the income after
the federal and state taxes are deducted. What are the corporation's
federal, state and local taxes?
Solution:
First identify the unknowns. What is the question? What are they
asking you to solve for? Since the problem asks for the corporation's
taxes, let x = federal tax liability, y = state tax liability, and z = local tax
liability.
Using the information, calculate the tax liabilities before deductions:
Federal Tax = 0.30($10,000,000) = $3,000,000
State Tax = 0.08($10,000,000) = $800,000
Local Tax = 0.04($10,000,000) = $400,000
Allowing for the deductions:
x = $3,000,000 - 0.3y -
0.3z
x + 0.3y + 0.3z = $3,000,000
y = $800,000 - 0.08x - 0.08z
0.08x + y + 0.08z = $800,000
z = $400,000 - 0.04x - 0.04y
0.04x + 0.04y + z = $400,000
Set up matrixes A, X, B

Use
the calculator to find
.

Store
the inverse matrix in matrix D.
Use matrix multiplication to solve X =
(B)
.


The federal tax liability is $2,752,202.09, the State tax liability is
$558,417.82 and the local tax liability is $267,575.20.
Testing the solution,
x + 0.3y + 0.3z = $3,000,000 $2,752,202.09
+ 0.3($558,417.82) + 0.3($267,575.20) = $3,000,000
0.08x + y + 0.08z = $800,000 0.08( $2,752,202.09)
+ $558,417.82 + 0.08($267,575.20) = $800,000
0.04x + 0.04y + z = $400,000 0.04( $2,752,202.09)
+ 0.04($558,417.82) + $267,575.20 = $400,000
The
linear system is consistent and independent (only one solution).
Why
Use Inverse Matrices to Solve Linear Systems?
Once you know the inverse matrix, it can be used to solve similar problems where
the coefficients are the same, but the answers are
different. Consider another company in the same tax bracket at the
corporation in Example 5 but their taxable income is $12,500,000.
Example
6:
Use the inverse matrix from Example 5 to solve the linear system:
A corporation has taxable income of $12,500,000. The federal tax rate is
30%, the state tax rate is 8%, and the local tax rate is 4%. The federal
taxes are based on the income after the state and local taxes are
deducted. The state taxes are based on the income after the federal and
local taxes are deducted. The local taxes are based on the income after
the federal and state taxes are deducted. What are the corporation's
federal, state and local taxes?
Solution:
Using the information, calculate the tax liabilities before deductions:
Federal Tax = 0.30($12,500,000) = $3,750,000
State Tax = 0.08($12,500,000) = $1,000,000
Local Tax = 0.04($12,500,000) = $500,000
The inverse matrix is stored in D.
Use matrix multiplication to solve X =
(B)
. Where
.
The federal tax liability is $3,440,252.62, the State tax liability is $698,022.27 and the local tax liability is
$334,469.00.
Testing the solution,
x + 0.3y + 0.3z = $3,000,000 $3,440,252.62
+ 0.3($698,022.27) + 0.3($334,469.00) rounds to $3,750,000
0.08x + y + 0.08z = $800,000 0.08( $3,440,252.62)
+ $698,022.27 + 0.08($334,469.00) rounds to $1,000,000
0.04x + 0.04y + z = $400,000 0.04( $3,440,252.62)
+ 0.04($698,022.27) + $334,469.00 rounds to $500,000
The
linear system is consistent and independent (only one solution).
Thus
the same inverse matrix can be used find the tax liabilities for all
corporations in the same tax bracket as the corporation
in Example 5.
ASSIGNMENT:
Try solving various types of problems from Section 2-6: 1 through 49 odd
Lesson 4
Lesson 6